This actually makes sense…

It also raises the question of whether or not virginity can be classified as a one-time trade item.. in that if someone takes your virginity, they have your virginity. If they later have sex with someone else, does the original person still have your virginity, or have they traded their newly acquired second-hand virginity to a third party.

(starts drawing charts on a whiteboard) Furthermore, if someone takes their virginity and has sex with another virgin, and takes that person’s virginity, do they give that person yours in exchange for theirs? Or, do they simply collect “virginity” until they have sex with someone who doesn’t have “virginity” anymore.

Then one must ask whether or not the new partner simply acquires only one of the “stockpiled virginities” (out of, let’s say, six collected)… or if it acts more in the manner of osmosis through a permeable membrane where there is an equalization and they get three of your six “stockpiled virginities”. Of course, then we would have the question of if it acts as such, and you have an odd number of collected virginity in the equation, is it possible to possess fractions of virginity. (I.e., if you have taken five people’s virginity and have sex with someone who has none, would you end up with 2.5 virginities each?)

Of course, this also would raise the question similar to Zeno’s Paradox… in that you can never get from Point A to Point B because you always have to travel half the distance… and since there are infinite halves, you can never get there. In this case, it would be can one ever completely lose their virginity because they would either be taking that of another virgin in exchange for theirs, or “splitting” theirs through osmotic equalization… where you will always end up with the same number as the other person. Example: You have yours, they have taken four people’s virginity, you now each have 2.5… you have sex with a virgin, causing the equation to become (2.5 + 1)/2 = 1.75 virginities each. You then have sex with someone who has none, and the equation is (1.75 + 0)/2 = 0.875 virginities each…

\*Wanders off jotting formulas and hypotheses in a notebook as he continues to mutter to himself.\*